Compound Interest
Learn Compound Interest calculation, formulas, half-yearly, quarterly interest, SI vs CI comparison in detail.
Learning Content
💰 Compound Interest - The Basics
Method of calculating interest on both principal and interest!
📚 What is compound interest?
Compound Interestis interest calculated on both principal and accrued interest.
called "interest on interest".
Interest accrues every period.
⭐ Key Terms
| artifice | English | Code | Explanation |
|---|---|---|---|
| Original | Principal | P | Initial investment amount |
| Interest rate | Rate of Interest | R | Annual interest percentage |
| Period | Time | n | How many years/periods? |
| compound interest | Compound Interest | CI | Total interest earned |
| sum | Amount | A | Principal + Compound Interest |
📐 Basic formula
A = P(1 + R/100)ⁿ
Amount = Principal × (1 + Rate/100)^Term
CI = A - P
Compound Interest = Amount - Principal
🔄 Interest Calculation Periods
| Type | Period | value of n | R value |
|---|---|---|---|
| Annually | Once a year | n = years | R = R% |
| Half-yearly | Once in 6 months | n = 2 × years | R = R/2 % |
| Quarterly | Once in 3 months | n = 4 × years | R = R/4 % |
| Monthly | Once a month | n = 12 × years | R = R/12 % |
📊 Simple understanding - example
Solution:
- P = ₹1000, R = 10%, n = 2
- A = P(1 + R/100)ⁿ
- A = 1000(1 + 10/100)²
- A = 1000 × (1.1)²
- A = 1000 × 1.21 =₹1210
CI:1210 - 1000 =₹210
SI (Comparison):1000 × 10 × 2 / 100 = ₹200
CI - SI = ₹10 more!
📈📉 Separate interest vs compound interest
| feature | Separate Interest (SI) | Compound Interest (CI) |
|---|---|---|
| Calculation of interest | On the original only | On principal + previous interest |
| Every year | Interest is equal | Interest will increase |
| For 1 year | SI = CI | SI = CI (equal to) |
| More than 1 year | SI < CI | CI > SI |
🎯 Important Notes
- SI = CI (equal) for 1 year
- CI - SI = SI × R / 100 for 2 years
- Half yearly interest > Annual interest
- Quarterly interest > Half yearly interest
- Compound interest is always higher than individual interest (over 1 year).
📐 Compound Interest - Key Formulas
All Formulas Essential for TNPSC Exam!
🔢 Basic formulas
| to find out | formula |
|---|---|
| Amount (A) |
A = P(1 + R/100)ⁿ |
| Compound Interest (CI) |
CI = A - P = P[(1 + R/100)ⁿ - 1] |
| Original (P) |
P = A / (1 + R/100)ⁿ |
📊 Half Yearly / Quarterly Formulas
| Type | formula |
|---|---|
| Half-yearly |
A = P(1 + R/200)²ⁿ |
| Quarterly |
A = P(1 + R/400)⁴ⁿ |
| Monthly |
A = P(1 + R/1200)¹²ⁿ |
💰 CI - SI Difference Formulas
| Period | CI - SI formula |
|---|---|
| 2 years |
CI - SI = P × (R/100)²= SI × R / 100 |
| 3 years |
CI - SI = P × (R/100)² × (3 + R/100) |
📈 Different ratios formula
A = P × (1 + R₁/100) × (1 + R₂/100) × (1 + R₃/100)
📉 Depreciation formulas
| condition | formula |
|---|---|
| Depreciation |
V = P(1 - R/100)ⁿ |
| Depopulation |
P = P₀(1 - R/100)ⁿ |
👥 Population / Growth Formulas
| condition | formula |
|---|---|
| Population increase |
P = P₀(1 + R/100)ⁿ |
| Price rise |
New Price = Old Price × (1 + R/100)ⁿ |
🔄 Double / Triple formulas
| condition | formula |
|---|---|
| (Rule of 72) |
n ≈ 72 / R |
| be n times |
(1 + R/100)ⁿ = times |
📋 Formula summary
To find CI:A-P
Half Yearly:R/2, n×2
2 Year CI-SI:P(R/100)²
Double:72/R years
📝 Compound Interest - 10 Key Examples
Frequently Asked Question Types in TNPSC Exam!
📌 Example 1: Basic CI calculation
Question:What is the amount if ₹8000 is invested for 2 years at 10% compound interest?
P = ₹8000, R = 10%, n = 2
A = P(1 + R/100)ⁿ
A = 8000(1 + 10/100)²
A = 8000 × (1.1)²
A = 8000 × 1.21 = ₹9680
📌 Example 2: Finding CI
Question:If ₹5000 is invested at 8% compound interest for 3 years what is the compound interest?
P = ₹5000, R = 8%, n = 3
A = 5000(1 + 8/100)³
A = 5000 × (1.08)³
A = 5000 × 1.259712 = ₹6298.56
CI = A - P = 6298.56 - 5000 = ₹1298.56
📌 Example 3: Half yearly interest
Question:If ₹10000 is invested for 1 year at 10% compounded semi-annually, the amount will be?
P = ₹10000, R = 10%, n = 1 year
Semiannually: R = 10/2 = 5%, n = 1×2 = 2
A = 10000(1 + 5/100)²
A = 10000 × (1.05)²
A = 10000 × 1.1025 = ₹11025
📌 Example 4: Quarterly interest
Question:CI if ₹16000 is invested for 9 months at 20% compounded quarterly?
P = ₹16000, R = 20%, n = 9 months = 3/4 year
Quarter: R = 20/4 = 5%, n = 3 (quarters)
A = 16000(1 + 5/100)³
A = 16000 × (1.05)³
A = 16000 × 1.157625 = ₹18522
CI = 18522 - 16000 = ₹2522
📌 Example 5: CI - SI Difference
Question:What is the difference of CI and SI for ₹5000 at 10% interest for 2 years?
P = ₹5000, R = 10%, n = 2
Method 1:
CI - SI = P × (R/100)²
CI - SI = 5000 × (10/100)²
CI - SI = 5000 × 0.01 = ₹50
Method 2:
SI = 5000 × 10 × 2 / 100 = ₹1000
CI - SI = SI × R/100 = 1000 × 10/100 = ₹50
📌 Example 6: Original invention
Question:A sum becomes ₹12100 in 2 years at 10% CI. What is original?
A = ₹12100, R = 10%, n = 2
P = A / (1 + R/100)ⁿ
P = 12100 / (1 + 10/100)²
P = 12100 / (1.1)²
P = 12100 / 1.21 = ₹10000
📌 Example 7: Different proportions
Question:₹10000 at 10% in first year, 20% in second year Amount in CI?
P = ₹10000, R₁ = 10%, R₂ = 20%
A = P × (1 + R₁/100) × (1 + R₂/100)
A = 10000 × (1 + 10/100) × (1 + 20/100)
A = 10000 × 1.1 × 1.2
A = 10000 × 1.32 = ₹13200
📌 Example 8: Doubling period
Question:How many years will it take for a sum to double at 12% compound interest?
R = 12%
To use Rule of 72:
n ≈ 72 / R
n ≈ 72 / 12 = 6 years
📌 Example 9: Population Growth
Question:A city has a population of 50000. Annual growth is 4%. Population after 2 years?
P₀ = 50000, R = 4%, n = 2
P = P₀(1 + R/100)ⁿ
P = 50000(1 + 4/100)²
P = 50000 × (1.04)²
P = 50000 × 1.0816 = 54080
Example 10: Depreciation
Question:A car costs ₹500000. Annual depreciation is 10%. Value after 3 years?
P = ₹500000, R = 10%, n = 3
V = P(1 - R/100)ⁿ
V = 500000(1 - 10/100)³
V = 500000 × (0.9)³
V = 500000 × 0.729 = ₹364500
📊 Important notes
- Note that (1.1)² = 1.21, (1.1)³ = 1.331
- Semiannual = R/2, n×2; Quarter = R/4, n×4
- CI - SI (2 year) = P(R/100)² is very important
- Growth: (1 + R/100), Depreciation: (1 - R/100)
⚡ Compound Interest - Crossroads
Super Tricks to Save Time in TNPSC Exam!
🚀 Trick 1: 2 Year CI Fast Track
Or
CI = SI + SI²/(100×P)
Example:₹10000, 10%, 2 yr
SI = 10000 × 10 × 2 / 100 = ₹2000
CI = 2000 + (2000 × 10/100) = 2000 + 200 =₹2200
🚀 Trick 2: CI - SI (2 years) Super Shortcut
Or
CI - SI = SI × R / (2 × 100)× 2
CI - SI = SI over 1 year SI
Example:₹5000, 10%, 2 yr
CI - SI = 5000 × (10/100)² = 5000 × 0.01 =₹50
🚀 Trick 3: Rule of 72 (Double)
| Interest rate | Double period |
|---|---|
| 6% | 72/6 = 12 years |
| 8% | 72/8 = 9 years |
| 9% | 72/9 = 8 years |
| 12% | 72/12 = 6 years |
🚀 Trick 4: Key (1+R/100)ⁿ values
| R% | n=2 | n = 3 |
|---|---|---|
| 5% | 1.1025 | 1.157625 |
| 10% | 1.21 | 1.331 |
| 20% | 1.44 | 1.728 |
| 25% | 1.5625 | 1.953125 |
🚀 Trick 5: Effective Rate of Interest
E = (1 + R/200)² - 1 = R + R²/400
Example:10% Effective Rate of Half Yearly Interest
E = 10 + 100/400 = 10 + 0.25 =10.25%
🚀 Trick 6: CI from SI Shortcut
For 3 years:CI = SI × (1 + R/100 + R²/30000)
Example:SI = ₹2000, R = 10%, 2 yr
CI = 2000 × (1 + 10/200) = 2000 × 1.05 =₹2100
🚀 Trick 7: Calculating CI by year
1st year CI = P × R/100
2nd year CI = (P + 1st CI) × R/100
3rd year CI = (P + 1st CI + 2nd CI) × R/100
Example:₹10000, 10%
1st year = 10000 × 10/100 = ₹1000
2nd year = 11000 × 10/100 = ₹1100
Total CI = 1000 + 1100 =₹2100
🚀 Trick 8: In the CI-SI difference to find the original
P = D × (100/R)²
Example:CI - SI = ₹40, R = 10%
P = 40 × (100/10)² = 40 × 100 =₹4000
🚀 Trick 9: Continuous CI values
Example:at 10% interest
If 1st year CI = ₹1000
2nd year CI = 1000 + (1000 × 10/100) =₹1100
3rd year CI = 1100 + (1100 × 10/100) =₹1210
🚀 Trick 10: Find the ratio
R = [(A₂ - A₁) / A₁] × 100
Example:A₁ = ₹11000, A₂ = ₹12100
R = [(12100 - 11000) / 11000] × 100
R = (1100/11000) × 100 =10%
📊 TNPSC Frequently Asked Categories
| Question type | Crossroads |
|---|---|
| Calculate CI | A = P(1+R/100)ⁿ, CI = A-P |
| CI - SI (2 Year) | P × (R/100)² |
| half year | R/2, n×2 |
| Double period | 72/R |
| Population | P(1+R/100)ⁿ |
| Depreciation | P(1-R/100)ⁿ |
💡 Important memory tips
- A = P(1+R/100)ⁿ- Basic formula
- CI = A - P- Always remember
- CI - SI = P(R/100)²- For 2 years
- 72/R- Years to double
- Growth: +R, Depreciation: -R
- Semiannual: R/2, n×2
- Quarter: R/4, n×4
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