Topic

Volume

Volume - Methods to calculate volume of cube, cuboid, cylinder, cone, sphere and other solids

Learning Content

📦 What is volume?

The amount of space a three-dimensional (3D) shape occupiescapacity(Volume) is called.

capacityin cubic units(Cubic Units) are measured.

📏 Units
unit of length Capacitance unit
meter (m) cubic meter (m³)
Centimeter (cm) Cubic cm (cm³)
millimeter (mm) Cubic mm (mm³)
feet (ft) cubic feet (cu.ft / ft³)
🔄 Unit Conversions
Change value
1 m³ 1000000 cm³ (10⁶ cm³)
1 cm³ 1000 mm³
1 liter 1000 cm³ = 1000 ml
1 m³ 1000 litres
1 Kilometer (kl) 1000 liters = 1 m³
1 cu.ft 28.317 liters ≈ 28.3 liters
📊 Basic Solids
1. Cube

A solid with six square faces

All edges are equal

Capacity = a³

2. Cuboid

A solid with six rectangular faces

Opposite faces are equal

Capacity = l × b × h

3. Cylinder

A solid with two circular bases

Capacitance = πr²h

4. Cone

A round bottom, a top

Capacitance = ⅓πr²h

5. Sphere

All points are equidistant from the center

Capacitance = (4/3)πr³

6. Hemisphere

Half of the sphere

Capacitance = (2/3)πr³

📚 Key Codes
Code Meaning English
a The edge of the cube Edge of Cube
l length Length
b width Breadth
h height Height
r Radius Radius
d diameter Diameter
l (slant) Slope height Slant Height
V capacity Volume
TSA Total surface area Total Surface Area
CSA/LSA Broadcasting Curved/Lateral Surface Area
🎯 Capacitance vs Surface Area
Volume Surface Area
Inside Space (3D) External Surface (2D)
Three-dimensional scale Two-dimensional scale
cubic meter, cubic cm Square meter, square cm.
Fill with water and sand to paint
Can be measured in liters In square units only
💡 Things to remember
  • π (pi)= 22/7 = 3.14159...
  • 1 liter= 1000 cm³ = 1000 ml
  • 1 m³= 1000 litres
  • Cone capacitance= ⅓ share of cylinder
  • Hemispherical capacity= ½ part of sphere
  • Diameter = 2 × radius(d = 2r)
  • Diagonal of cube= a√3

📐 Capacitance formulas - all solids

All Capacity & Surface Formulas for TNPSC Exam!

🔲 Cube - edge = a
capacity V = a³
Total surface area TSA = 6a²
(Page 4) LSA = 4a²
Diagonal d = a√3
margin (from capacity) a = ∛V
Number of edges 12
Number of faces 6
Number of vertices 8
📦 Cuboid - l × b × h
capacity V = l × b × h
Total surface area TSA = 2(lb + bh + hl)
(Page 4) LSA = 2h(l + b)
Diagonal d = √(l² + b² + h²)
Addition of margins 4(l + b + h)
🥫 Cylinder - radius r, height h
capacity V = πr²h
Broadcasting CSA = 2πrh
Total surface area TSA = 2πr(r + h)
Subsurface πr²
Hollow Cylinder:
V = πh(R² - r²)
TSA = 2π(R + r)(h + R - r)
🍦 Cone - radius r, height h, slope l
capacity V = ⅓πr²h
Broadcasting CSA = πrl
Total surface area TSA = πr(r + l)
Slope height l = √(r² + h²)
height h = √(l² - r²)
💡Memory:Capacitance of cone = ⅓ of cylinder (if same r, h)
🌍 Sphere - radius r
capacity V = (4/3)πr³
surface SA = 4πr²
Capacitance in diameter V = (π/6)d³
surface in diameter SA = πd²
🌓 Hemisphere - radius r
capacity V = (2/3)πr³
Broadcasting CSA = 2πr²
Total surface area TSA = 3πr²
💡Note:TSA = CSA + Base area = 2πr² + πr² = 3πr²
🔺Prism
capacity V = Area × Height
Broadcasting LSA = Circumference × Height
Total surface area TSA = LSA + 2 × Subsurface
Triangular League:
V = (½ × feet × height) × length
🔻 Koumbak / Pyramid
capacity V = ⅓ × base × height
Broadcasting LSA = ½ × Circumference × Slope Height
Total surface area TSA = LSA + Substrate
🍩 Ring / Torus
capacity V = 2π²Rr² R = major radius, r = minor radius
surface SA = 4π²Rr
⚡ Frustum of Cone

r = top radius, R = bottom radius, h = height, l = slope height

capacity V = ⅓πh(R² + r² + Rr)
Broadcasting CSA = πl(R + r)
Total surface area TSA = π[R² + r² + l(R + r)]
Slope height l = √[h² + (R − r)²]
🔄 Key relationships
  • Cone : Cylindrical : Sphere(same r, h=2r) → capacitance ratio =1 : 3 : 2
  • Cone capacitance= ⅓ × cylindrical capacity (same base, height)
  • Hemispherical capacity= ½ × spherical capacitance
  • spherical surface= 4 × Area of ​​great circle = 4πr²

📝 Capacity - Solved Examples

10 Important Questions for TNPSC Exam

Question 1: Cube

Question:The perimeter of the cube is 6 cm. If so, find the capacity and total surface area.


Solution:

Margin a = 6 cm.

Capacitance V = a³ = 6³ =216 cubic cm.

Total surface TSA = 6a² = 6 × 36 =216 sq. cm.

Question 2: Cuboid

Question:The length of the tank is 10 m, width 8 m, height 5 m. If so, how many liters of water will it take?


Solution:

l = 10 m., b = 8 m., h = 5 m.

Capacity V = l × b × h = 10 × 8 × 5 =400 cubic m.

1 cubic m. = 1000 litres

∴ Water = 400 × 1000 =4,00,000 liters = 400 kg litres

Question 3: Cylinder

Question:The radius of the cylinder is 7 cm and the height is 10 cm. If so, see capacitance and amplitude. (π = 22/7)


Solution:

Radius r = 7 cm, height h = 10 cm.

Capacitance V = πr²h = (22/7) × 7 × 7 × 10

V = 22 × 7 × 10 =1540 cubic cm.

Area of ​​curvature CSA = 2πrh = 2 × (22/7) × 7 × 10

CSA = 2 × 22 × 10 =440 sq. cm.

Question 4: Cone

Question:The radius of the cone is 6 cm and the height is 8 cm. If so, see capacity and slope height.


Solution:

Radius r = 6 cm, height h = 8 cm.

Height of slope l = √(r² + h²) = √(36 + 64) = √100 =10 cm

Capacitance V = ⅓πr²h = ⅓ × (22/7) × 6 × 6 × 8

V = (22 × 36 × 8) / (7 × 3) = 6336/21 =301.7 cubic cm

Question 5: Sphere

Question:The radius of the sphere is 21 cm. If so, find capacity and surface area.


Solution:

Radius r = 21 cm.

Capacitance V = (4/3)πr³ = (4/3) × (22/7) × 21 × 21 × 21

V = (4 × 22 × 21 × 21 × 21) / (3 × 7)

V = (4 × 22 × 21 × 21 × 3) / 1 =38808 cubic cm.

Area SA = 4πr² = 4 × (22/7) × 21 × 21

SA = 4 × 22 × 63 =5544 sq. cm.

Question 6: Hemisphere

Question:The radius of the hemisphere is 14 cm. If so, find capacity and total surface area.


Solution:

Radius r = 14 cm.

Capacitance V = (2/3)πr³ = (2/3) × (22/7) × 14 × 14 × 14

V = (2 × 22 × 14 × 14 × 2) / 3 = 17248/3 =5749.33 cubic cm.

Total surface area TSA = 3πr² = 3 × (22/7) × 14 × 14

TSA = 3 × 22 × 28 =1848 sq. cm.

Question 7: Melting & Recasting

Question:6 cm Melt the edged cube to 3 cm. How many spheres will you get if you make spheres of radius ?


Solution:

Cubic capacity = a³ = 6³ = 216 cubic cm.

Spherical capacitance = (4/3)πr³ = (4/3) × (22/7) × 27 = (4 × 22 × 27)/(3 × 7)

= 2376/21 = 113.14 cubic cm.

Number of spheres = 216/113.14 ≈1.9 ≈ 1 sphere

(whole spheres only)

Question 8: Cylindrical Tank

Question:2.1 m. The radius is 5 m. A tall cylindrical tank should be painted. If ₹25 per 1 sq m, what is the total cost?


Solution:

r = 2.1 m. = 21/10 m., h = 5 m.

Total surface area TSA = 2πr(r + h)

= 2 × (22/7) × (21/10) × (21/10 + 5)

= 2 × (22/7) × (21/10) × (71/10)

= 2 × 22 × 3 × 71/100 = 93.72 sq m.

Cost = 93.72 × 25 =₹2343

Question 9: Frustum

Question:The top radius of the bucket is 28 cm, the bottom radius is 21 cm, and the height is 24 cm. If so, see capacity.


Solution:

R = 28 cm, r = 21 cm, h = 24 cm.

Capacitance V = ⅓πh(R² + r² + Rr)

= ⅓ × (22/7) × 24 × (784 + 441 + 588)

= ⅓ × (22/7) × 24 × 1813

= (22 × 24 × 1813) / (7 × 3)

= 957528/21 =45596.57 cubic cm. ≈ 45.6 liters

Question 10: Combined Solid

Question:A hemisphere is placed on top of a cylinder. The radius of the cylinder is 7 cm and the height of the cylinder is 10 cm. If so, see total capacity.


Solution:

r = 7 cm, h = 10 cm.

Cylinder capacity = πr²h = (22/7) × 49 × 10 = 1540 cubic cm.

Hemispherical capacitance = (2/3)πr³ = (2/3) × (22/7) × 343

= (2 × 22 × 49) / 3 = 2156/3 = 718.67 cubic cm.

Total capacity = 1540 + 718.67 =2258.67 cubic cm.

📚 Additional practice questions
  1. The cubic capacity is 512 cubic cm. If, margin =8 cm
  2. If the cylindrical radius is doubled, the capacitance =4 times
  3. If radius of sphere is multiplied by 3, capacitance =27 times
  4. Cone, Cylindrical, Sphere (same r, h=2r) Capacitance ratio =1:3:2
  5. 1000 liters =1 cubic meter

⚡ Capacitance - Crossroads

Super Tricks to Save Time in TNPSC Exam!

🚀 Trick 1: Key Cylindrical Values
Radius (r) Height (h) Capacitance (πr²h)
7 1 154
7 10 1540
7 h 154h
14 1 616
21 1 1386
💡Memory:If r=7, then πr² = 154 (easy to remember!)
🚀 Trick 2: Dimensional change → Capacitance change
Cube:Margin n times → capacity n³ times
Sphere:Radius n times → Capacity n³ times
Cylinder:r only n times → capacitance n² times
Cylinder:h only n times → capacity n times
Change Capacitance change
2 times 8 times (2³)
3 times 27 times (3³)
½ times ⅛ times
🚀 Trick 3: Cone : Cylindrical : Sphere ratio
If the same radius r and height h = 2r:

Cone : Cylindrical : Sphere =1 : 3 : 2

Example:r = 7, h = 14

Cone = ⅓ × 154 × 14 = 718.67

Cylinder = 154 × 14 = 2156

Sphere = (4/3) × 154 × 7 = 1437.33

Ratio ≈ 1 : 3 : 2 ✓

🚀 Trick 4: Melting account
Capacitance does not change when melting!

Old Capacity = New Capacity
Count = Capacity of old / Capacity of a new item

Example:6 cm Make the cube 1 cm. Convert to cubes?

Old capacity = 6³ = 216

New capacity = 1³ = 1

Number = 216/1 =216 cubes

🚀 Trick 5: Liter Conversion Shortcuts
Change Quick method
Cubic cm → Liter ÷ 1000
Liter → cubic cm × 1000
cubic m. → Liter × 1000
liter → cubic m ÷ 1000
Cubic cm → ml Same (1 cm³ = 1 ml)
🚀 Trick 6: Spherical formula memory
Sphere:V = (4/3)πr³ → "four three by r cubed"
Hemisphere:V = (2/3)πr³ → half of sphere
Spherical Surface:SA = 4πr² → "four by r squared"
Radius Capacitance is (4/3)πr³ The surface area is 4πr²
7 1437.33 616
14 11498.67 2464
21 38808 5544
🚀 Trick 7: Cube quick calculation
Total surface TSA = 2(lb + bh + hl)
= 2 × (first two + middle two + last two)

Example:l=5, b=4, h=3

TSA = 2(20 + 12 + 15) = 2 × 47 =94 square units

🚀 Trick 8: % increase → capacity increase
Cube/Sphere:If x% increase
Increase in capacity = (3x + 3x²/100 + x³/10000)%

Summary (for small x):≈ 3x%

Example:10% increase in sphere radius

Increase in capacitance ≈ 3 × 10 = 30%

Precisely: (1.1)³ = 1.331 → 33.1% increase

🚀 Trick 9: Cone Slope Height Shortcut
l² = r² + h²(Pythagorean Theorem)

3:4:5 ratio: r=3k, h=4k if l=5k
5:12:13 ratio: r=5k, h=12k if l=13k

Example:r=6, h=8

This is a 3:4 ratio (k=2), so l = 5 × 2 =10

🚀 Trick 10: Water filling time
Time = Capacity / Rate

Rate = litres/minute or litres/hour

Example:1000 liter tank, 20 liter/min

Time = 1000/20 =50 minutes

📊 TNPSC Frequently Asked Categories
Question type Crossroads
cubic capacity V = a³
Cylinder capacity V = πr²h (r=7 → 154h)
Cone capacitance V = ⅓πr²h (⅓ of cylinder)
Sphere Capacitance V = (4/3)πr³
Melting and casting Old V = New V
Liter conversion 1 m³ = 1000 L, 1 cm³ = 1 ml
💡 Important memory tips
  • π = 22/7- If the radius is 7 times
  • Cone = ⅓ cylinder(same feet, height)
  • Hemisphere = ½ sphere
  • 1:3:2- cone:cylindrical:sphere (r equals, h=2r)
  • Radius n times → Capacity n³ times
  • 1 liter = 1000 cm³ = 1000 ml
  • 1 m³ = 1000 liters = 1 kiloliter
  • Diagonal of cube = a√3
DISCLAIMER

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Please verify official sources before appearing for exams.